Cement-lime mortar for plastering walls. How much does a cube of solution weigh? Decorative plaster “Bark beetle” for walls

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Correct counting of ingredients for cooking mortar mixture affects basic qualities brickwork(strength, durability), cement-sand screed for leveling the floor and other work in which the solution is used.

When calculating the selection of proportions of cement and sand, it is necessary to take into account that when the grade of cement increases, the amount of this material must be reduced to obtain a solution of the same grade. Sometimes, when installing screeds, the uncured surface is sprinkled with cement - this increases the strength of the coating, but more cement is used. We will describe how to calculate how much cement is needed per cubic meter (1m3) of solution, depending on its brand.

The need for cement per cubic meter of solution may depend on:

  • purpose of the mortar mixture (for masonry, for plaster, for flooring). In construction, cement-sand ( masonry mortar or mortar for screeding), clay and lime mortars (for plastering surfaces). So in the first solution, cement and sand are taken in a ratio of 1 to 3 or 1 to 4. The latter option is used for laying partitions, and for load-bearing walls It is better to use a high strength solution of 1 to 3 or higher. In lime mortar, the main binder is lime, the volume fraction of cement is a third in relation to ready solution. If used clay mixture, then the amount of cement in it is 1 to 9;
  • brand of mortar, which characterizes its compressive strength after complete hardening (27 days);

The composition of the solution characterizes the ratio between the binder and fine aggregate.

Let's consider how much cement M400 is needed to obtain different brands mortar, the weight of cement corresponds to its amount per 1 m3 of mortar;

  • to prepare the M10 grade of mortar you need 81 kg of cement;
  • for grade M25 you need 133 kg of cement;
  • for grade M50 you need 178 kg of cement;
  • for grade M75 you need 245 kg of cement;
  • for grade M100 you need 304 kg of cement;
  • for grade M150 you need 414 kg of cement;
  • for grade M200 you need 510 kg of cement.

You can calculate how much cement is needed per cubic meter (1 m3) of solution based on the proportion of 1 to 3 or 1 to 4, knowing that a 10 liter bucket of cement weighs 14 kilograms. You also need to know that the same amount of water used to prepare the solution is the same as cement.

Consider the ratio of 1 to 3. With this ratio we have 5 parts (1 part cement, 3 parts sand and 1 part water).

Therefore, the cube will contain 200 liters of cement, 600 liters of sand and 200 liters of water. In terms of weight, a cube of such a solution requires 20×14 = 280 kg.

Now let's calculate the ratio 1 to 4 (1 part cement, 4 parts sand and 1 part water). Here you need a little more water, so one part will correspond to 1000/6=150l. We calculate the amount of cement per cube of such a solution: 15×14 = 210 kg.

To determine how much sand and cement is needed per 1 cubic meter of mortar, it is important to know its purpose. For the preparation of masonry, plaster, foundation and other types of mixtures it is used different ratio dry materials. The consumption of sand and cement per 1 m3 of mortar varies for each type of work, and often other dry or liquid formulations, increasing moisture resistance, strength, changing the rate of hardening of the mixture, etc.

What determines cement consumption for different solutions?

The preparation of cement mortar, the proportions of which may differ, requires strict adherence to technology and the correct determination of the ratio of components. To use different grades of concrete, different amounts of cement and sand are used. Remembering the proportions of cement and sand is not enough for high-quality construction; it is better to understand the principle.

Requires strict adherence to the technology for preparing cement mortar

Main factors influencing consumption:

  • the amount of fillers in the mixture. The greater the proportion of crushed stone and sand, the higher the cement consumption per 1 m3 of solution. Cement is the binder of the components, which is responsible for holding all the fillers together. The ratio of bulk mixtures determines the amount of cement;
  • brand of cement. As the grade increases, the strength of the final structure increases. It is worth remembering that the grade of the final mixture is significantly lower than dry cement, since sand is added to the composition, and gravel or slag can also be added;
  • brand of solution. The cement-sand mortar is also divided by grade. For all types of work, GOST has recommended brands. After determining the desired brand construction mixture, you can choose the right brand of cement. For example, to obtain an M100 mixture from M500 cement, you will need to mix 1 part Portland cement, 5.8 parts sand and 8.1 parts crushed stone. If the final goal is M450 solution, a proportion of M500 cement (C:P:SH) will be required: 1:1.4:2.9;

The density of cement plays a secondary role here, since it directly depends on the brand of cement, but it is necessary to know it during the calculation process.

Conclusion: how much cement is required per 1 m3 of mortar depends on the required strength mortar and brand of the original mixture.


The density of cement directly depends on the brand of cement

Types and brands of mixtures

The introduction of the concept of “cement grade” helps to calculate the cement consumption per cube of mortar if the input parameters are known. To prepare a solution with the same construction characteristics from different brands cement mixture, different proportions of fillers will be required. Cement is produced in production, starting from grade M100, but due to the low structural strength, the material is practically not used.

The most popular cements are M400 and M500, but some other types have also become widespread. The choice of mixture depends on the scope of application of the material.

The main areas of use of cement grade:

  • M300 cement is used in installation construction, as well as during the manufacture of monolithic structures;
  • M400 cement is successfully used in monolithic construction and during the preparation of reinforced concrete;
  • M500 cement is actively used in the construction of buildings or slabs that must be resistant to moisture or located in water. Areas of application of this concrete mixture are quite wide: the creation of sidewalks, the construction of asbestos-cement structures, the formation of large concrete masses and all kinds of foundations;

M400 and M500 cements are the most popular
  • M600 cement is used to create prefabricated structures and foundations that are subject to high loads;
  • M700 is a suitable grade of cement for the construction of highly loaded and stressed structures.

Material consumption rates per cubic meter of different solutions

Today there are 4 main areas of use of concrete: foundation, masonry, screed and plaster. In each case, special requirements are imposed on the building mixture, which makes the choice of cement and its consumption different. The greatest consumption of cement per cube of concrete occurs when it is necessary to make masonry or plaster. The consumption of materials per 1 m3 of foundation mortar is slightly lower due to the use of a large filler fraction: slag, crushed stone or gravel.

GOST has records of cement consumption rates per 1m3 of mortar, taking into account the purpose of the mortar. Designation of concrete per cubic meter. meters is a generally accepted system of measurement.


Cement consumption rates per 1m3 of solution

Consumption standards per 1 m3 using M500 cement:

  • on M100 – 170 kg;
  • on M150 – 200 kg;
  • on M200 – 240 kg;
  • on M250 - 300 kg;
  • on M300 – 350 kg;
  • on M400 – 400 kg;
  • on M500 – 450 kg.

Consumption rates for cement and sand per cube of foundation mortar

Calculation of cement for foundation calculator is the simplest way understand how much material is required and the number of necessary components. Concrete calculations can be done with high accuracy and manually.

To determine how much cement is needed per 1 m3 of solution, we recommend following simple instructions:


Cement consumption rates for foundations
  1. We determine the appropriate brand of cement mortar. Usually, when creating a foundation, it is advisable to use a solution of M100-M300. For low-level buildings, M100 is sufficient, if you plan to build several floors - M150, and M200 and higher are used in construction multi-storey buildings and any structures that are subject to increased strength requirements. If the foundation is built under wooden building, an M50 solution is sufficient.
  2. We select the brand of cement. For standard tasks, M300-M400 is suitable in the proportion of cement to sand 1 to 3. When using cement M500 - 1 to 5.

How many kg of cement in 1 m3 of solution:

  • in M50 when using M400 – 380 kg;
  • in M100 when preparing concrete from M300 cement – ​​214 kg;
  • in M200 with cement M400 – 286 kg;
  • in M300 at M500 – 382 kg.

The data is presented if the cube contains 2-4 parts of sand and 3 parts of crushed stone.

Consumption rates of cement and sand per cube of masonry mortar

To prepare cement mortar for wall construction, a proportion of 1 to 4 is most often used. Thus, the cement consumption per cubic meter will be 0.25 m3 or 325 kg, and the sand consumption per 1 m3 of mortar will be 0.75 m3 or 1200 kg.


Cement consumption rates for masonry

Table 1: Mortar consumption for walls of different thicknesses

To calculate how many bags of cement are needed, just multiply 325 kg by the consumption per cubic meter, for example, walls of one brick - 0.221. You will get 72 kg of cement for laying 1 m3 of wall, provided that the composition does not contain other components (lime, clay, etc.).

Consumption rates of cement and sand per cube of screed mortar

Cement consumption per 1 cubic meter of solution is calculated according to similar rules as in previous mixtures. The recommended mixing ratio is 1 to 3. Difficulties in calculations often appear at the stage of determining the volume of the solution, so let’s consider clear example. It is necessary to fill a surface of 3x4 m or 12 m2. The layer thickness will be 30 mm.


Cement consumption rates for screed

Calculation of cement for screed from the example:

  1. We are counting required volume solution: 12 m2 * 0.03 m = 0.36 m3.
  2. We determine the brand of cement, M200 solution is often used, and we use it as an example. We will cook from M500, and according to the standards, the consumption will be 410 kg.
  3. We count required amount bags of cement: 410 kg * 0.36 m3 = 148 kg - this is 6 small or 3 standard bags of 50 kg.
  4. We determine the cost of sand. To do this we multiply specific gravity 1 m3 of sand for the required amount ready mixture: 1600 kg/m3 * 0.36 m3 = 576 kg, and since the proportion of sand in general solution 75%, further multiplied by 0.75 - 432 kg of sand. Sand consumption per 1 cubic meter of solution is approximately 1200 kg/m3.

Consumption rates of cement and sand per cube of plaster mortar

Cement consumption per 1 m2 of plaster greatly depends on the quality of the wall covering, required thickness layer and number of large holes. Again, for clarity, we will give an example of the calculation, remembering that a mixture of 1 to 4 is usually used. Input parameters: it is necessary to cover 60 m2 of walls with plaster 2.5 cm thick.

Calculations of cement and sand consumption per 1 m3:

  1. Amount of materials in cubes. For 1 m2 you will need 1 * 0.025 = 0.025 m3 of solution, where a fifth is cement and the rest is sand. By using elementary mathematics We determine that 0.02 m3 of sand and 0.005 m3 of cement will be required.
  2. For the entire area of ​​the wall you will need: 0.02 * 60 = 1.2 m3 of sand and 0.005 * 60 = 0.3 m3 of cement.
  3. The specific density of cement is on average 1400 kg/m3 (fresh 1100-1200 kg/m3, and compacted 1500-1600 kg/m3). We determine the cement consumption: 0.3 * 1400 = 350 kg.
  4. Required weight of sand: 1.2 * 1600 = 1920 kg, we remind you that 1600 kg/m3 is the specific gravity of sand.

All calculations are simple; it is only important to choose the right brand of the initial mixture and the desired brand of output solution. Everything else can be easily calculated in a few mathematical steps.

Plaster cement-lime-sand mixture.

When performing construction and is very often used plaster cement-lime-sand mixture for brick, concrete and wooden walls. And although the popularity of gypsum plaster mixtures is enormous, many customers still choose cement-lime mortars for plastering. Lime-cement mortar for plastering walls has many positive characteristics, but its main advantage is its relatively low price. This material is flexible and also very durable. Cement-lime plaster has excellent adhesion to the surface and is usually used for finishing interior walls rooms with high humidity.

Cement-lime mortar composition.

IN composition of cement-lime mortar consists of three components: binder (cement and lime), filler (sand) and water. To make the mortar, you will need fresh cement of grade 400 or 500. When cement is stored for a long time in conditions that are far from ideal, the grade of cement decreases and the properties deteriorate accordingly. After a month of such storage, grade M 500 will turn into M 450, and in six months the cement may lose a quarter of its properties.

River or quarry sand must be sifted through a mesh with a mesh size of 3-5 mm. To prepare plaster it is usually used quarry sand, since it contains a small amount, so the solution is a little softer and more flexible. Also, to increase plasticity, you can add PVA glue (0.5 liters per 20 liters of solution), liquid soap(approximately 0.2 liters per 20 liters of solution) or add plasticizers.

If the lime is not slaked, then it must be slaked. Lime is poured into a barrel and filled with water, observing basic rules safety precautions and using goggles and gloves for protection, since due to chemical reaction a huge amount of heat is released.

Cement-lime mortar proportions.

The proportions for plastering with cement-lime mortar during production differ depending on the specific construction finishing works ah planned to use this material. One of the most common options for finishing walls with plaster: 1:1:6 or 1:2:9 (one part cement: one part lime milk: six parts sand).

Consumption of cement-lime plaster per 1 m2

The consumption of cement-lime plaster per 1 m2 with a layer thickness of 5 mm is approximately 7 kg. By volume, solution consumption per 1 sq. meter with a layer thickness of 5 mm is approximately 5-6 liters or 0.005-0.006 m3. It is recommended to apply a layer thickness from 5 mm to 30 mm. In practice, they take 1 bag of cement weighing 50 kg. and 40 kg. slaked lime, 550 kg of sand and 100 liters of water. At proper preparation plaster mixture using lime-cement mortar, you can achieve high-quality wall finishing and reduce several times How much does 1 cube of plaster weigh - mixtures for wall finishing, the weight of 1 m3 of plaster. Number of kilograms in 1 cubic meter plaster mortar, number of tons in 1 cubic meter of plaster composition, kg in 1 m3 of bark beetle plaster. The volumetric density of plaster is the specific gravity of the plaster mortar - the building mixture.

What do we want to learn today? How much does 1 cube of plaster, plaster composition, weight of 1 m3 of plaster - mixture for wall finishing weigh? No problem, you can find out the number of kilograms or the number of tons at once, the mass of the building mixture (the weight of one cubic meter of plaster composition, the weight of one cube of mortar for plastering walls, the weight of one cubic meter of bark beetle, the weight of 1 m3 of composition for finishing work) are indicated in Table 1. If If anyone is interested, you can skim the small text below and read some explanations. How is the amount of substance, material, liquid or gas we need measured? Except for those cases when it is possible to reduce the calculation of the required quantity to the counting of goods, products, elements in pieces (piece counting), it is easiest for us to determine required quantity based on volume and weight (mass). In everyday life, the most common unit of volume measurement for us is 1 liter. However, the number of liters suitable for household calculations is not always an applicable method for determining the volume for economic activity. In addition, liters in our country have not become a generally accepted “production” and trade unit for measuring volume. One cubic meter, or in its abbreviated version - one cube, turned out to be quite convenient and popular for practical use unit of volume. We are accustomed to measuring almost all substances, liquids, materials and even gases in cubic meters. It's really convenient. After all, their costs, prices, rates, consumption rates, tariffs, supply contracts are almost always tied to cubic meters (cubes), and much less often to liters. No less important for practical activities is knowledge of not only the volume, but also the weight (mass) of the substance occupying this volume: in in this case we are talking about how much 1 cubic meter of plaster mortar weighs (1 cubic meter of bark beetle, 1 cubic meter of mortar for plastering walls, 1 m3 of plaster). Knowing mass and volume gives us a fairly complete idea of ​​quantity. Site visitors, when asking how much 1 cube of plaster composition for wall finishing weighs, often indicate specific units of mass in which they would like to know the answer to the question. As we noticed, most often they want to know the weight of 1 cubic meter of plaster mortar (1 cubic meter of mortar for plastering walls, 1 cubic meter of bark beetle, 1 m3 of composition for finishing work) in kilograms (kg) or in tons (t). Essentially, you need kg/m3 or t/m3. These are closely related units that determine the amount of mixture for finishing walls. In principle, a fairly simple independent conversion of weight (mass) from tons to kilograms and vice versa is possible: from kilograms to tons. However, as practice has shown, for most site visitors more convenient option It would be nice to immediately know how many kilograms 1 cubic meter (1 m3) of plaster - a mixture for plastering walls - weighs, or how many tons 1 cubic meter (1 m3) of plaster - a building mixture - weighs, without converting kilograms into tons or vice versa - the number of tons into kilograms per cubic meter (one cubic meter, one cubic meter, one m3). Therefore, in Table 1 we indicated how much 1 cubic meter of plaster mortar weighs (1 cubic meter of bark beetle, 1 cubic meter of plaster) in kilograms (kg) and in tons (t). Choose the table column that you need yourself. By the way, when we ask how much 1 cubic meter (1 m3) of plaster composition weighs, we mean the number of kilograms of the mixture for wall finishing or the number of tons. However, from a physical point of view, we are interested in the density finishing composition or specific gravity. The mass of a unit volume or the amount of substance contained in a unit volume is bulk density or specific gravity. In this case bulk density of the plaster mortar and specific gravity of the plaster. The density of a solution for plastering walls and the specific gravity of the bark beetle in physics are usually measured not in kg/m3 or in tons/m3, but in grams per cubic centimeter: g/cm3. Therefore, in Table 1, the specific gravity of the plaster and the density of the plaster mortar (synonyms) are indicated in grams per cubic centimeter (g/cm3)

Table 1. How much does 1 cube of plaster weigh, the weight of 1 m3 of plaster. Volume density of the plaster mortar and specific gravity of the composition for finishing work in g/cm3. How many kilograms are there in a cube of plaster composition, tons in 1 cubic meter of bark beetle, kg in 1 cubic meter of mixture for plastering walls, tons in 1 m3 of building mixture.

In one cube of solution (in 1 m3 of solution) there are 2000 - 2200 kilograms (kg).

One kilogram of solution contains 0.0005 - 0.00045 cubic meters.

To convert kilograms (kg) to cubes and vice versa, use .

How is the calculation made:

The calculation is made using a simple physical formula: Mass = Density * Volume.

The density of the solution depends on the type of solution and ranges from 2000 to 2200 kg/m3.

Hence:

1) If you need to determine the mass of a solution, then multiply the density of the solution by its volume.

2) If you need to determine the volume of a solution, then divide the mass of the solution by its density.

Theory:

Theoretical and practical concepts of converting one unit of measurement to another are based on centuries of experience scientific research humanity in applied fields of knowledge.

Mass is a characteristic of a body, which is a measure of gravitational interaction with other bodies.

Volume is the amount of space occupied by a body or substance.

Density is a physical quantity defined as the ratio of the mass of a body to the volume occupied by this body.

Practice:

This page provides the simplest answer to the question how many kilograms (kg) are in a cube (m3) of solution and vice versa. One cube of solution is equal to 2000 - 2200 kilograms (kg). One kilogram of solution is equal to 0.0005 - 0.00045 cubic meters.

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