Volume of a parallelepiped. Formulas for finding the volume of a parallelepiped Rectangular parallelepiped product ab

Subscribe
Join the “koon.ru” community!
In contact with:

The figures in Figure 175, a and b, consist of an equal number of identical cubes. About such figures we can say that they are volumes are equal. The rectangular parallelepipeds shown in Figure 175, c and d, consist of 18 and 9 identical cubes, respectively. Therefore, we can say that the volume of the first of them is twice the volume of the second.

You often come across such a quantity as volume in everyday life: the volume of a fuel tank, the volume of a swimming pool, the volume of a classroom, gas or water consumption indicators on meters, etc.

Experience tells you that equal containers have equal volumes. For example, identical barrels have equal volumes.

If a container is divided into several parts, then the volume of the entire container is equal to the sum of the volumes of its parts. For example, the volume of a two-chamber refrigerator is equal to the sum of the volumes of its chambers.

These examples illustrate the following properties of the volume of a figure.

1) Equal figures have equal volumes.

2) The volume of a figure is equal to the sum of the volumes of the figures it consists of.

As in the case of other quantities (length, area), you should enter a unit of volume.

For the unit of volume measurement, I choose a cube whose edge is equal to a unit segment. This cube is called single.

cubic millimeter. They write 1 mm 3.

I call the volume of a cube with an edge of 1 cm cubic centimeter. They write 1 cm 3.

I call the volume of a cube with an edge of 1 mm cubic decimeter. They write 1 dm 3.

When measuring volumes of liquids and gases, 1 dm 3 is called liter. They write: 1 l. So, 1 l = 1 dm 3.

If the volume of the red cube (see Fig. 175, e) is taken as one, then the volumes of the figures in Fig. 175, a, b, c and d are respectively 5, 5, 18 and 9 cubic units.

If the length, width and height of a rectangular parallelepiped are respectively 5 cm, 6 cm, 4 cm, then this parallelepiped can be divided into 5 * 6 * 4 unit cubes (Fig. 176). Therefore, its volume is 5 * 6 * 4 = 120 cm 3.

The volume of a rectangular parallelepiped is equal to the product of its three dimensions.

V=abc

where V is the volume, a, b, and c are the measurements of the cuboid, expressed in the same units.

Since all edges of a cube are equal, its volume is calculated using the formula:

V = a 3

where a is the length of the cube edge. That is why the third power of a number is called the cube of a number.

The product of the length a and width b of a rectangular parallelepiped is equal to the area S of its base: S = ab(Fig. 177). Let us denote the height of the rectangular parallelepiped by the letter h. Then the volume V of the rectangular parallelepiped is equal to V = abh.

V = abh = (ab)h = Sh.

So, we got another formula for calculating the volume of a rectangular parallelepiped:

V = Sh

The volume of a rectangular parallelepiped is equal to the product of the area of ​​the base and the height.

Example. What should be the height of a tank shaped like a rectangular parallelepiped so that its volume is 324 dm 3 and its bottom area is 54 dm 2?

Solution. From the formula V = Sh it follows that h = V: S. Then the required height h of the tank can be calculated as follows:

h = 324: 54 = 6 (dm).

Answer: 6 dm.

showPlots(;0 noAxes0 );

Rice. 2.1: Two parallelepipeds

2.0.6 Unit of volume.

When measuring volumes, the volume of a cube in which each edge is equal to a linear unit is taken as a unit of volume. Thus, cubic meters (m3), cubic centimeters (cm3), etc. are used.

2.1 Volume of a parallelepiped.

2.1.1 Theorem on the volume of a regular cuboid

The volume of a rectangular parallelepiped is equal to the product of its three dimensions.

In such a brief expression, this theorem should be understood as follows: the number expressing the volume of a rectangular parallelepiped in a cubic unit is equal to the product of the numbers expressing its three dimensions in the corresponding linear unit, i.e. in a unit that is an edge of a cube, the volume of which is taken to be a cubic unit. Thus, if x is a number expressing the volume of a cuboid in cubic centimeters, and a; b and c

numbers expressing its three dimensions in linear centimeters, then the theorem states that x = abc In the proof, we will especially consider the following three cases: 1) The dimensions are expressed in integers. Let, for example, the measurements be (2.2) AB = a; BC = b and BD = c, where a; b and c are some integers (for example, as shown in our figure: a = 4; b = 2 and c = 5). Then the base of the parallelepiped contains ab such squares, each of which represents a corresponding square unit. Each of these squares can obviously accommodate one cubic unit. Then you get a layer (shown in 2.2) consisting of ab cubic units. Since the height of this layer is equal to one linear unit, and the height of the entire parallelepiped contains c such units, then c such layers can be placed inside the parallelepiped. Therefore, the volume of this parallelepiped is equal to abc cubic units. 2) Measurements are expressed in fractional numbers. Let the dimensions of the parallelepiped be:

m n ; p q ; r s

(some of these fractions may equal a whole number). Reducing the fractions to the same denominator, we have:

mqs ngs ; pns qns; rnq snq:

Let us take nqs 1 fraction of a linear unit as a new (auxiliary) unit

tsu length. Then in this new unit of measurement of this parallelepiped they will be expressed in integers, namely:

(mqs) (pns) (rnq);

and therefore, according to what has been proven (in case 1), the volume of a parallelepiped is equal to the product (mqs) (pns) (rnq), if this volume is measured by a new cubic unit corresponding to a new linear unit. There are such cubic units

prostrate in one cubic unit corresponding to the former linear unit - q

tse, contains (nqs)3 ; so the new cubic unit is (nqs) 3

former. Therefore, the volume of the parallelepiped, expressed in the previous units, is equal to

(mqs) (pns) (rnq) =

(nqs)3

3) Measurements are expressed in irrational numbers. Let this parallelepiped (2.3), which for brevity we denote by a single letter Q, have the dimensions:

AB = ; AC = ; AD = ;

where are all the numbers; and or only some of them are irrational. Each of the numbers; and can be represented as an infinite decimal fraction. Let us take approximate values ​​of these fractions with n decimal places, first with a deficiency and then with an excess. Values ​​with a disadvantage will be denoted by n; n ; n values ​​with excess n 0 ; n 0 ; n 0 . Let us plot on edge AB, starting from point A, two segments AB1 = n and AB2 = n 0 . On the edge AC from the same point A we plot the segments AC1 = n and AC2 = n 0 and on the edge AD from the same point the segments AD1 = n and n 0. In this case we will have

AB1< AB < AB2 ; AC1 < AC < AC2 ; AD1 < AD < AD2 :

Let's now build two auxiliary parallelepipeds: one (let's call it Q1) with dimensions AB1; AC1 and AD1 and another (let's call it Q2) with measurements AB2; AC2 and AD2. The parallelepiped Q1 will fit entirely inside the parallelepiped Q, and the parallelepiped Q2 will contain the parallelepiped Q inside it. According to what has been proven (in case 2) we will have:

Q1 = n n n ; (1)

Q2 = n 0 n 0 n 0 ; (2)

and the volume Q1< объема Q2 .

Let's now start increasing the number n. This means that we take approximate values ​​of the numbers; ; gamma with more and more accuracy. Let's see how the volumes of parallelepipeds Q1 change in this case

and Q 2 With an unlimited increase in n, the volume Q1 obviously increases

And by virtue of equality (1) with an infinite increase in n has its predominant

In fact, the limit of the product(n ; n ; n ). Volume Q2 obviously decreases and

by virtue of equality (2) has the limit of the product n 0 ; n 0 ; n 0 . But from algebra it is known that both products are n; n ; n and n 0 ; n 0 ; n 0 with an unlimited increase in n have a common limit, which is the product of irrational numbers. We take this limit as a measure of the volume of the parallelepiped Q: volume Q = . It can be proven that the volume determined in this way satisfies the conditions established for volume. In fact, with this definition of volume, equal parallelepipeds obviously have equal volumes. Therefore, the first condition is satisfied. Let us now divide this parallelepiped Q into two by a plane parallel to its base: Q1 and Q2 (2.4). Then we will have:

Q1 = AB AC AD;

Q2 = AB AA1 AD;

Q3 = A1 B1 A1 C A1 D1 :

Adding the last two equalities term by term and noting that A1 B1 = AB and A1 D1 = AD, we obtain volume Q1 + volume Q2 = AB AA1 AD + AB A1 C AD = AB AD(AA1 + A1 C) = AB AD AC, from here we obtain :

Q1 + Q2 = Q:

Consequently, the second condition is also satisfied if the parallelepiped is folded from two parts obtained by cutting it with a plane parallel to one of the faces.

set2D(0; 20; 4; 20);

;0 dash0 );

;0 dash0 );

;0 dash0 );

dash0);

p8 = pointsPlot(4

[ 0A 0; 0 B 0; 0 C 0; 0 a 0; 0 b 0; 0 c 0; 0 D 0];

showPlots(;0 noAxes0 );

set2D(3; 12; 2; 13);

;0 dash0 );

;0 dash0 );

Rice. 2.2: Parallelepiped

;0 dash0 );

dash0);

;0 dash0 );

TEXT TRANSCRIPT OF THE LESSON:

Since the fifth grade we have known the formula for finding the volume of a rectangular parallelepiped. Today we will remember this formula and prove the theorem “Volume of a rectangular parallelepiped”

Let's prove the theorem: The volume of a rectangular parallelepiped is equal to the product of its three dimensions.

Given: parallelepiped

a, b, c are its measurements.

V is the volume of the parallelepiped.

Prove: V = abc.

Proof:

1. Let a, b, c be finite decimal fractions, where the number of decimal places is no more than n (n > 1).

Then Numbers a. 10n, b. 10n, c. 10n - integers.

Let us divide each edge of the parallelepiped into equal segments of length and draw planes perpendicular to the edges through the points of division.

The parallelepiped will be divided into abc.103n equal cubes with an edge. Let's find the volume of each small cube will be equal to one divided by ten to the nth power raised to the cube. Raising the numerator and denominator to the cube, we get (one cubed is equal to one, and 10 to the nth power cubed is equal to 10 to the power 3n) the quotient of one and 10 to the power 3n.

Because the volume of each such cube is equal, and the number of these cubes is abc multiplied by, then the volume of a rectangular parallelepiped is found by multiplying the number of cubes by the volume of a small cube. Then we obtain the expression: the volume of a rectangular parallelepiped is equal to the product abc multiplied by 10 to the power of 3n quotient of units and 10 to the power of 3n .

Reducing by 10 to the power of 3n, we find that the volume of a rectangular parallelepiped is equal to abc or the product of its three dimensions.

So V = abc.

2. Let us prove that if at least one of the dimensions a, b, c is an infinite decimal fraction, then the volume of the parallelepiped is also equal to the product of its three dimensions.

Let аn, bn, cn be finite decimal fractions obtained from the numbers a, b, discarding all digits after the decimal point in each of them, starting with (n + 1). Then a is greater than or equal to a with index and less than or equal to a with index n prime

an< a < an",

where a is the nth prime equal to the sum of a is the nth and one divided by ten to the nth power =

for b and c, we write down similar inequalities and write them one below the other

an< a < an"

bn< b < bn"

cn< c < cn",

Multiplying these three inequalities, we get: the product abc is greater than or equal to the product of a nth by b nth and by c nth and less than or equal to a nth prime by b nth prime and by c nth prime:

anbncn abc< an"bn"cn". (1)

According to what was proven in paragraph 1., the left side is the volume of a parallelepiped with sides anbncn, that is, Vn, and the right side is the volume of a parallelepiped with sides an"bn"cn, that is, Vn".

Because parallelepiped P, that is, a parallelepiped with dimensions a, b, c contains a parallelepiped Pn, that is, a parallelepiped with sides an, bn, cn, and itself is contained in a parallelepiped Pn", that is, a parallelepiped with sides an", bn", cn" then the volume V of the parallelepiped P is enclosed between Vn = anbncn and Vn "= an"bn"cn",

those. anbncn< V < an"bn"cn". (2)

With an unlimited increase in n, the quotient of one and 10 to the power of 3n will become arbitrarily small, and therefore the numbers anbncn and an"bn"cn" will differ as little as possible from each other. Consequently, the number V differs as little as desired from the number abc. So they are equal:

V = abc. The theorem has been proven.

Corollary 1. The volume of a rectangular parallelepiped is equal to the product of the area of ​​the base and the height.

The base of a cuboid is a rectangle. Let the length of the rectangle be a and the width be b, let the height be denoted by h=c. Then we find the area of ​​the rectangle using the formula. Let's substitute into the formula to find the volume V = abc instead of the product we write. We get the formula

Corollary 2. The volume of a right prism whose base is a right triangle is equal to the product of the area of ​​the base and the height.

Given a rectangular prism, angle A at the base is right. Let's build a rectangular prism to a rectangular parallelepiped (see drawing). A rectangular parallelepiped consists of two rectangular prisms, which are equal because they have equal bases and heights. Accordingly, the area of ​​the rectangle is equal to two areas of right triangles ABC. Therefore, the volume of a rectangular prism is equal to half the volume of a cuboid (when multiplied) or the product of the base of a right triangle and the height.

Task 1. Find the volume of the polyhedron shown in the figure (all dihedral angles are right angles).

We find the volume of a rectangular parallelepiped using the formula:

This figure consists of two rectangular parallelepipeds.

Let be the volume of a full parallelepiped with dimensions 4, 3, 3. Then this is the volume of a small “cut out” parallelepiped with dimensions 3, 1, 1.

To find the volume of a polyhedron, you need to find the difference between the volumes V1 and V2

We find the volume V1 as the product of its measurements, denote them a1, b1, c1, we obtain its volume equal to

For a small “cut out” parallelepiped, the volume V2 is equal to the product of its measurements, we denote them as a2, b2, c2, then we get

Now let’s find the volume of the polyhedron V as the difference between V1 and V2, we get V=

Answer: V of the polyhedron is 33

VOLUME OF A RECTANGULAR PARALLELEPIPED The volume of a rectangular parallelepiped is equal to the product of its three dimensions, i.e. the formula holds

Exercise 1 The edges of a rectangular parallelepiped extending from one vertex are equal to 1, 2, 3. Find the volume of the parallelepiped. Answer: 6.

Exercise 2 Two edges of a rectangular parallelepiped emerging from one vertex are equal to 1, 2. The volume of the parallelepiped is equal to 3. Find the third edge of the parallelepiped emerging from the same vertex. Answer: 1, 5.

Exercise 3 The area of ​​the face of a rectangular parallelepiped is equal to 2. The edge perpendicular to this face is equal to 3. Find the volume of the parallelepiped. Answer: 6.

Exercise 4 Two edges of a rectangular parallelepiped coming from one vertex are equal to 1, 2. The diagonal of the parallelepiped is equal to 3. Find the volume of the parallelepiped. Answer: 4.

Exercise 6 How many times will the volume of a cube increase if its edge is doubled? Answer: 8 times.

Exercise 9 Two edges of a rectangular parallelepiped extending from the same vertex are equal to 1, 2. The surface area of ​​the parallelepiped is 10. Find the volume of the parallelepiped. Answer: 2.

Exercise 10 The edge of a rectangular parallelepiped is equal to 1. The diagonal is equal to 3. The surface area of ​​the parallelepiped is equal to 16. Find the volume of the parallelepiped. Answer: 4.

Exercise 12 The areas of the three faces of a rectangular parallelepiped are 1, 2, 3. Find the volume of the parallelepiped. The volume of the parallelepiped is equal to Answer:

Exercise 19 A rectangular parallelepiped is described around a cylinder whose base radius and height are equal to 1. Find the volume of the parallelepiped. Solution: The edges of a parallelepiped are 2, 2 and 1. Its volume is 4.

Exercise 20 A parallelepiped is described around a unit sphere. Find its volume. Solution: The edges of the parallelepiped are equal to 2. Its volume is equal to 8.

Exercise 21 Find the volume of a cube inscribed in a unit octahedron. Solution: The edge of the cube is equal The volume of the cube is equal

Exercise 22 Find the volume of a cube circumscribed about a unit octahedron. Solution: The edge of the cube is equal The volume of the cube is equal

Exercise 23 Find the volume of a cube inscribed in a unit dodecahedron. Solution: The edge of the cube is equal The volume of the cube is equal

Exercise 24 Can the areas of all faces of a parallelepiped be less than 1, and the volume of the parallelepiped be greater than 100? Answer: No, the volume will be less than 1.

Exercise 25 Can the areas of all faces of a parallelepiped be greater than 100, but the volume of the parallelepiped be less than 1? Answer: Yes.

Exercise 27 The four faces of a parallelepiped are rectangles with sides 1 and 2. What is the largest volume this parallelepiped can have? Solution. The required parallelepiped is a rectangular parallelepiped, the two remaining faces of which are squares with side 2. Its volume is 4. Answer: 4.

What is the largest volume that a parallelepiped can have if it is inscribed in a straight cylinder whose base radius and height are equal to 1? Answer: 2.

Simply put, these are vegetables cooked in water according to a special recipe. I will consider two initial components (vegetable salad and water) and the finished result - borscht. Geometrically, it can be thought of as a rectangle, with one side representing lettuce and the other side representing water. The sum of these two sides will indicate borscht. The diagonal and area of ​​such a “borscht” rectangle are purely mathematical concepts and are never used in borscht recipes.


How do lettuce and water turn into borscht from a mathematical point of view? How can the sum of two line segments become trigonometry? To understand this, we need linear angular functions.


You won't find anything about linear angular functions in math textbooks. But without them there can be no mathematics. The laws of mathematics, like the laws of nature, work regardless of whether we know about their existence or not.

Linear angular functions are addition laws. See how algebra turns into geometry and geometry turns into trigonometry.

Is it possible to do without linear angular functions? It’s possible, because mathematicians still manage without them. The trick of mathematicians is that they always tell us only about those problems that they themselves know how to solve, and never talk about those problems that they cannot solve. Look. If we know the result of addition and one term, we use subtraction to find the other term. All. We don’t know other problems and we don’t know how to solve them. What should we do if we only know the result of the addition and do not know both terms? In this case, the result of the addition must be decomposed into two terms using linear angular functions. Next, we ourselves choose what one term can be, and linear angular functions show what the second term should be so that the result of the addition is exactly what we need. There can be an infinite number of such pairs of terms. In everyday life, we get along just fine without decomposing the sum; subtraction is enough for us. But in scientific research into the laws of nature, decomposing a sum into its components can be very useful.

Another law of addition that mathematicians don't like to talk about (another of their tricks) requires that the terms have the same units of measurement. For salad, water, and borscht, these could be units of weight, volume, value, or unit of measurement.

The figure shows two levels of difference for mathematical . The first level is the differences in the field of numbers, which are indicated a, b, c. This is what mathematicians do. The second level is the differences in the field of units of measurement, which are shown in square brackets and indicated by the letter U. This is what physicists do. We can understand the third level - differences in the area of ​​​​the objects being described. Different objects can have the same number of identical units of measurement. How important this is, we can see in the example of borscht trigonometry. If we add subscripts to the same unit designation for different objects, we can say exactly what mathematical quantity describes a particular object and how it changes over time or due to our actions. Letter W I will designate water with a letter S I'll designate the salad with a letter B- borsch. This is what linear angular functions for borscht will look like.

If we take some part of the water and some part of the salad, together they will turn into one portion of borscht. Here I suggest you take a little break from borscht and remember your distant childhood. Remember how we were taught to put bunnies and ducks together? It was necessary to find how many animals there would be. What were we taught to do then? We were taught to separate units of measurement from numbers and add numbers. Yes, any one number can be added to any other number. This is a direct path to the autism of modern mathematics - we do it incomprehensibly what, incomprehensibly why, and very poorly understand how this relates to reality, because of the three levels of difference, mathematicians operate with only one. It would be more correct to learn how to move from one unit of measurement to another.

Bunnies, ducks, and little animals can be counted in pieces. One common unit of measurement for different objects allows us to add them together. This is a children's version of the problem. Let's look at a similar problem for adults. What do you get when you add bunnies and money? There are two possible solutions here.

First option. We determine the market value of the bunnies and add it to the available amount of money. We got the total value of our wealth in monetary terms.

Second option. You can add the number of bunnies to the number of banknotes we have. We will receive the amount of movable property in pieces.

As you can see, the same addition law allows you to get different results. It all depends on what exactly we want to know.

But let's get back to our borscht. Now we can see what will happen for different angle values ​​of linear angular functions.

The angle is zero. We have salad, but no water. We can't cook borscht. The amount of borscht is also zero. This does not mean at all that zero borscht is equal to zero water. There can be zero borscht with zero salad (right angle).


For me personally, this is the main mathematical proof of the fact that . Zero does not change the number when added. This happens because addition itself is impossible if there is only one term and the second term is missing. You can feel about this as you like, but remember - all mathematical operations with zero were invented by mathematicians themselves, so throw away your logic and stupidly cram the definitions invented by mathematicians: “division by zero is impossible”, “any number multiplied by zero equals zero” , “beyond the puncture point zero” and other nonsense. It is enough to remember once that zero is not a number, and you will never again have a question whether zero is a natural number or not, because such a question loses all meaning: how can something that is not a number be considered a number? It's like asking what color an invisible color should be classified as. Adding a zero to a number is the same as painting with paint that is not there. We waved a dry brush and told everyone that “we painted.” But I digress a little.

The angle is greater than zero but less than forty-five degrees. We have a lot of lettuce, but not enough water. As a result, we will get thick borscht.

The angle is forty-five degrees. We have equal quantities of water and salad. This is the perfect borscht (forgive me, chefs, it's just math).

The angle is greater than forty-five degrees, but less than ninety degrees. We have a lot of water and little salad. You will get liquid borscht.

Right angle. We have water. All that remains of the salad are memories, as we continue to measure the angle from the line that once marked the salad. We can't cook borscht. The amount of borscht is zero. In this case, hold on and drink water while you have it)))

Here. Something like this. I can tell other stories here that would be more than appropriate here.

Two friends had their shares in a common business. After killing one of them, everything went to the other.

The emergence of mathematics on our planet.

All these stories are told in the language of mathematics using linear angular functions. Some other time I will show you the real place of these functions in the structure of mathematics. In the meantime, let's return to borscht trigonometry and consider projections.

Saturday, October 26, 2019

I watched an interesting video about Grundy series One minus one plus one minus one - Numberphile. Mathematicians lie. They did not perform an equality check during their reasoning.

This echoes my thoughts about .

Let's take a closer look at the signs that mathematicians are deceiving us. At the very beginning of the argument, mathematicians say that the sum of a sequence DEPENDS on whether it has an even number of elements or not. This is an OBJECTIVELY ESTABLISHED FACT. What happens next?

Next, mathematicians subtract the sequence from unity. What does this lead to? This leads to a change in the number of elements of the sequence - an even number changes to an odd number, an odd number changes to an even number. After all, we added one element equal to one to the sequence. Despite all the external similarity, the sequence before the transformation is not equal to the sequence after the transformation. Even if we are talking about an infinite sequence, we must remember that an infinite sequence with an odd number of elements is not equal to an infinite sequence with an even number of elements.

By putting an equal sign between two sequences with different numbers of elements, mathematicians claim that the sum of the sequence DOES NOT DEPEND on the number of elements in the sequence, which contradicts an OBJECTIVELY ESTABLISHED FACT. Further reasoning about the sum of an infinite sequence is false, since it is based on a false equality.

If you see that mathematicians, in the course of proofs, place brackets, rearrange elements of a mathematical expression, add or remove something, be very careful, most likely they are trying to deceive you. Like card magicians, mathematicians use various manipulations of expression to distract your attention in order to ultimately give you a false result. If you cannot repeat a card trick without knowing the secret of deception, then in mathematics everything is much simpler: you don’t even suspect anything about deception, but repeating all the manipulations with a mathematical expression allows you to convince others of the correctness of the result obtained, just like when -they convinced you.

Question from the audience: Is infinity (as the number of elements in the sequence S) even or odd? How can you change the parity of something that has no parity?

Infinity is for mathematicians, like the Kingdom of Heaven is for priests - no one has ever been there, but everyone knows exactly how everything works there))) I agree, after death you will be absolutely indifferent whether you lived an even or odd number of days, but... Adding just one day into the beginning of your life, we will get a completely different person: his last name, first name and patronymic are exactly the same, only the date of birth is completely different - he was born one day before you.

Now let’s get to the point))) Let’s say that a finite sequence that has parity loses this parity when going to infinity. Then any finite segment of an infinite sequence must lose parity. We don't see this. The fact that we cannot say for sure whether an infinite sequence has an even or odd number of elements does not mean that parity has disappeared. Parity, if it exists, cannot disappear without a trace into infinity, like in a sharpie’s sleeve. There is a very good analogy for this case.

Have you ever asked the cuckoo sitting in the clock in which direction the clock hand rotates? For her, the arrow rotates in the opposite direction to what we call “clockwise”. As paradoxical as it may sound, the direction of rotation depends solely on which side we observe the rotation from. And so, we have one wheel that rotates. We cannot say in which direction the rotation occurs, since we can observe it both from one side of the plane of rotation and from the other. We can only testify to the fact that there is rotation. Complete analogy with the parity of an infinite sequence S.

Now let's add a second rotating wheel, the plane of rotation of which is parallel to the plane of rotation of the first rotating wheel. We still can't say for sure in which direction these wheels rotate, but we can absolutely tell whether both wheels rotate in the same direction or in the opposite direction. Comparing two infinite sequences S And 1-S, I showed with the help of mathematics that these sequences have different parities and putting an equal sign between them is a mistake. Personally, I trust mathematics, I don’t trust mathematicians))) By the way, to fully understand the geometry of transformations of infinite sequences, it is necessary to introduce the concept "simultaneity". This will need to be drawn.

Wednesday, August 7, 2019

Concluding the conversation about, we need to consider an infinite set. The point is that the concept of “infinity” affects mathematicians like a boa constrictor affects a rabbit. The trembling horror of infinity deprives mathematicians of common sense. Here's an example:

The original source is located. Alpha stands for real number. The equal sign in the above expressions indicates that if you add a number or infinity to infinity, nothing will change, the result will be the same infinity. If we take the infinite set of natural numbers as an example, then the considered examples can be represented in this form:

To clearly prove that they were right, mathematicians came up with many different methods. Personally, I look at all these methods as shamans dancing with tambourines. Essentially, they all boil down to the fact that either some of the rooms are unoccupied and new guests are moving in, or that some of the visitors are thrown out into the corridor to make room for guests (very humanly). I presented my view on such decisions in the form of a fantasy story about the Blonde. What is my reasoning based on? Relocating an infinite number of visitors takes an infinite amount of time. After we have vacated the first room for a guest, one of the visitors will always walk along the corridor from his room to the next one until the end of time. Of course, the time factor can be stupidly ignored, but this will be in the category of “no law is written for fools.” It all depends on what we are doing: adjusting reality to mathematical theories or vice versa.

What is an “endless hotel”? An infinite hotel is a hotel that always has any number of empty beds, regardless of how many rooms are occupied. If all the rooms in the endless "visitor" corridor are occupied, there is another endless corridor with "guest" rooms. There will be an infinite number of such corridors. Moreover, the “infinite hotel” has an infinite number of floors in an infinite number of buildings on an infinite number of planets in an infinite number of universes created by an infinite number of Gods. Mathematicians are not able to distance themselves from banal everyday problems: there is always only one God-Allah-Buddha, there is only one hotel, there is only one corridor. So mathematicians are trying to juggle the serial numbers of hotel rooms, convincing us that it is possible to “shove in the impossible.”

I will demonstrate the logic of my reasoning to you using the example of an infinite set of natural numbers. First you need to answer a very simple question: how many sets of natural numbers are there - one or many? There is no correct answer to this question, since we invented numbers ourselves; numbers do not exist in Nature. Yes, Nature is great at counting, but for this she uses other mathematical tools that are not familiar to us. I’ll tell you what Nature thinks another time. Since we invented numbers, we ourselves will decide how many sets of natural numbers there are. Let's consider both options, as befits real scientists.

Option one. “Let us be given” one single set of natural numbers, which lies serenely on the shelf. We take this set from the shelf. That's it, there are no other natural numbers left on the shelf and nowhere to take them. We cannot add one to this set, since we already have it. What if you really want to? No problem. We can take one from the set we have already taken and return it to the shelf. After that, we can take one from the shelf and add it to what we have left. As a result, we will again get an infinite set of natural numbers. You can write down all our manipulations like this:

I wrote down the actions in algebraic notation and in set theory notation, with a detailed listing of the elements of the set. The subscript indicates that we have one and only set of natural numbers. It turns out that the set of natural numbers will remain unchanged only if one is subtracted from it and the same unit is added.

Option two. We have many different infinite sets of natural numbers on our shelf. I emphasize - DIFFERENT, despite the fact that they are practically indistinguishable. Let's take one of these sets. Then we take one from another set of natural numbers and add it to the set we have already taken. We can even add two sets of natural numbers. This is what we get:

The subscripts "one" and "two" indicate that these elements belonged to different sets. Yes, if you add one to an infinite set, the result will also be an infinite set, but it will not be the same as the original set. If you add another infinite set to one infinite set, the result is a new infinite set consisting of the elements of the first two sets.

The set of natural numbers is used for counting in the same way as a ruler is for measuring. Now imagine that you added one centimeter to the ruler. This will be a different line, not equal to the original one.

You can accept or not accept my reasoning - it is your own business. But if you ever encounter mathematical problems, think about whether you are following the path of false reasoning trodden by generations of mathematicians. After all, studying mathematics, first of all, forms a stable stereotype of thinking in us, and only then adds to our mental abilities (or, conversely, deprives us of free-thinking).

pozg.ru

Sunday, August 4, 2019

I was finishing a postscript to an article about and saw this wonderful text on Wikipedia:

We read: "... the rich theoretical basis of the mathematics of Babylon did not have a holistic character and was reduced to a set of disparate techniques, devoid of a common system and evidence base."

Wow! How smart we are and how well we can see the shortcomings of others. Is it difficult for us to look at modern mathematics in the same context? Slightly paraphrasing the above text, I personally got the following:

The rich theoretical basis of modern mathematics is not holistic in nature and is reduced to a set of disparate sections, devoid of a common system and evidence base.

I won’t go far to confirm my words - it has a language and conventions that are different from the language and conventions of many other branches of mathematics. The same names in different branches of mathematics can have different meanings. I want to devote a whole series of publications to the most obvious mistakes of modern mathematics. See you soon.

Saturday, August 3, 2019

How to divide a set into subsets? To do this, you need to enter a new unit of measurement that is present in some of the elements of the selected set. Let's look at an example.

May we have plenty A consisting of four people. This set is formed on the basis of “people.” Let us denote the elements of this set by the letter A, the subscript with a number will indicate the serial number of each person in this set. Let's introduce a new unit of measurement "gender" and denote it by the letter b. Since sexual characteristics are inherent in all people, we multiply each element of the set A based on gender b. Notice that our set of “people” has now become a set of “people with gender characteristics.” After this we can divide the sexual characteristics into male bm and women's bw sexual characteristics. Now we can apply a mathematical filter: we select one of these sexual characteristics, no matter which one - male or female. If a person has it, then we multiply it by one, if there is no such sign, we multiply it by zero. And then we use regular school mathematics. Look what happened.

After multiplication, reduction and rearrangement, we ended up with two subsets: the subset of men Bm and a subset of women Bw. Mathematicians reason in approximately the same way when they apply set theory in practice. But they don’t tell us the details, but give us the finished result - “a lot of people consist of a subset of men and a subset of women.” Naturally, you may have a question: how correctly has the mathematics been applied in the transformations outlined above? I dare to assure you that, in essence, the transformations were done correctly; it is enough to know the mathematical basis of arithmetic, Boolean algebra and other branches of mathematics. What it is? Some other time I will tell you about this.

As for supersets, you can combine two sets into one superset by selecting the unit of measurement present in the elements of these two sets.

As you can see, units of measurement and ordinary mathematics make set theory a relic of the past. A sign that all is not well with set theory is that mathematicians have come up with their own language and notation for set theory. Mathematicians acted as shamans once did. Only shamans know how to “correctly” apply their “knowledge.” They teach us this “knowledge”.

In conclusion, I want to show you how mathematicians manipulate
Let's say Achilles runs ten times faster than the tortoise and is a thousand steps behind it. During the time it takes Achilles to run this distance, the tortoise will crawl a hundred steps in the same direction. When Achilles runs a hundred steps, the tortoise crawls another ten steps, and so on. The process will continue ad infinitum, Achilles will never catch up with the tortoise.

This reasoning became a logical shock for all subsequent generations. Aristotle, Diogenes, Kant, Hegel, Hilbert... They all considered Zeno's aporia in one way or another. The shock was so strong that " ... discussions continue to this day; the scientific community has not yet been able to come to a common opinion on the essence of paradoxes ... mathematical analysis, set theory, new physical and philosophical approaches were involved in the study of the issue; none of them became a generally accepted solution to the problem..."[Wikipedia, "Zeno's Aporia". Everyone understands that they are being fooled, but no one understands what the deception consists of.

From a mathematical point of view, Zeno in his aporia clearly demonstrated the transition from quantity to . This transition implies application instead of permanent ones. As far as I understand, the mathematical apparatus for using variable units of measurement has either not yet been developed, or it has not been applied to Zeno’s aporia. Applying our usual logic leads us into a trap. We, due to the inertia of thinking, apply constant units of time to the reciprocal value. From a physical point of view, this looks like time slowing down until it stops completely at the moment when Achilles catches up with the turtle. If time stops, Achilles can no longer outrun the tortoise.

If we turn our usual logic around, everything falls into place. Achilles runs at a constant speed. Each subsequent segment of his path is ten times shorter than the previous one. Accordingly, the time spent on overcoming it is ten times less than the previous one. If we apply the concept of “infinity” in this situation, then it would be correct to say “Achilles will catch up with the turtle infinitely quickly.”

How to avoid this logical trap? Remain in constant units of time and do not switch to reciprocal units. In Zeno's language it looks like this:

In the time it takes Achilles to run a thousand steps, the tortoise will crawl a hundred steps in the same direction. During the next time interval equal to the first, Achilles will run another thousand steps, and the tortoise will crawl a hundred steps. Now Achilles is eight hundred steps ahead of the tortoise.

This approach adequately describes reality without any logical paradoxes. But this is not a complete solution to the problem. Einstein’s statement about the irresistibility of the speed of light is very similar to Zeno’s aporia “Achilles and the Tortoise”. We still have to study, rethink and solve this problem. And the solution must be sought not in infinitely large numbers, but in units of measurement.

Another interesting aporia of Zeno tells about a flying arrow:

A flying arrow is motionless, since at every moment of time it is at rest, and since it is at rest at every moment of time, it is always at rest.

In this aporia, the logical paradox is overcome very simply - it is enough to clarify that at each moment of time a flying arrow is at rest at different points in space, which, in fact, is motion. Another point needs to be noted here. From one photograph of a car on the road it is impossible to determine either the fact of its movement or the distance to it. To determine whether a car is moving, you need two photographs taken from the same point at different points in time, but you cannot determine the distance from them. To determine the distance to a car, you need two photographs taken from different points in space at one point in time, but from them you cannot determine the fact of movement (of course, you still need additional data for calculations, trigonometry will help you). What I want to draw special attention to is that two points in time and two points in space are different things that should not be confused, because they provide different opportunities for research.
I'll show you the process with an example. We select the “red solid in a pimple” - this is our “whole”. At the same time, we see that these things are with a bow, and there are without a bow. After that, we select part of the “whole” and form a set “with a bow”. This is how shamans get their food by tying their set theory to reality.

Now let's do a little trick. Let’s take “solid with a pimple with a bow” and combine these “wholes” according to color, selecting the red elements. We got a lot of "red". Now the final question: are the resulting sets “with a bow” and “red” the same set or two different sets? Only shamans know the answer. More precisely, they themselves do not know anything, but as they say, so it will be.

This simple example shows that set theory is completely useless when it comes to reality. What's the secret? We formed a set of "red solid with a pimple and a bow." The formation took place in four different units of measurement: color (red), strength (solid), roughness (pimply), decoration (with a bow). Only a set of units of measurement allows us to adequately describe real objects in the language of mathematics. This is what it looks like.

The letter "a" with different indices denotes different units of measurement. The units of measurement by which the “whole” is distinguished at the preliminary stage are highlighted in brackets. The unit of measurement by which the set is formed is taken out of brackets. The last line shows the final result - an element of the set. As you can see, if we use units of measurement to form a set, then the result does not depend on the order of our actions. And this is mathematics, and not the dancing of shamans with tambourines. Shamans can “intuitively” come to the same result, arguing that it is “obvious,” because units of measurement are not part of their “scientific” arsenal.

Using units of measurement, it is very easy to split one set or combine several sets into one superset. Let's take a closer look at the algebra of this process.

Return

×
Join the “koon.ru” community!
In contact with:
I am already subscribed to the community “koon.ru”