Reinforcing steel (reinforcement) is used to reinforce reinforced concrete structures.
On this page you can calculate the weight of reinforcement and find out what diameters of reinforcing steel there are.
Rebar weight calculator
ANSWER: the weight of the reinforcement is 0 kg
Calculator how many meters of reinforcement are in 1 ton
ANSWER: 0 meters. (0 rods per millimeter)
The reinforcement is manufactured in accordance with GOST 5781-82 “Hot-rolled steel for the reinforcement of reinforced concrete structures. Technical conditions" and GOST R 52544-2006 "Rolled welded reinforcement of periodic profile of classes A500C and B500C for reinforcement of reinforced concrete structures. Technical conditions" Depending on the mechanical properties, reinforcing steel is divided into classes A-I (A240), A-II (A300) , A-III (A400); A-IV (A600), A-V (A800), A-VI (A1000). In the designation A500C and B500C, the letter A means hot-rolled or thermomechanically strengthened reinforcing bars, the letter B means cold-deformed reinforcing bars, and the letter C means weldable.
The number in the designation shows the rounded value of the yield strength in N/mm 2. The yield strength is a mechanical characteristic of a material that characterizes the stress at which strain continues to increase without increasing the load.
Weight of a meter of reinforcement. Number of meters of reinforcement per ton.
| Profile number (nominal rod diameter) | Weight of 1 m profile, theoretical, kg | Number of meters of reinforcement in 1 ton, m |
| 4 | 0,099 | 10101,010 |
| 5 | 0,154 | 6493,506 |
| 6 | 0,222 | 4504,504 |
| 8 | 0,395 | 2531,645 |
| 10 | 0,617 | 1620,745 |
| 12 | 0,888 | 1126,126 |
| 14 | 1,210 | 826,446 |
| 16 | 1,580 | 632,911 |
| 18 | 2,000 | 500,000 |
| 20 | 2,470 | 404,858 |
| 22 | 2,980 | 335,570 |
| 25 | 3,850 | 259,740 |
| 28 | 4,830 | 207,037 |
| 32 | 6,310 | 158,478 |
| 36 | 7,990 | 125,156 |
| 40 | 9,870 | 101,317 |
| 45 | 12,480 | 80,128 |
| 50 | 15,410 | 64,892 |
| 55 | 18,650 | 53,619 |
| 60 | 22,190 | 45,065 |
| 70 | 30,210 | 33,101 |
| 80 | 39,460 | 25,342 |
Every person who is building his own house or just planning construction work often asks the question: “How much reinforcement in meters is there in a ton?” This question is natural, since all calculations for this product on a construction site are performed in meters, and when purchased - in tons.
Types of fittings
Before looking for the answer to the question: “How much reinforcement in meters is there in a ton?”, you need to clearly understand what kind of material it is and what the nuances of its use are.
Along with classic steel reinforcement, fiberglass reinforcement is now widely used. This is a fairly new material on the Russian building materials market. Therefore, many people prefer steel, since it has already been tested for decades.
For various types of work, depending on the need, reinforcement of various diameters (from 0.6 to 4 cm) can be used. Another difference is the presence of special ribs on the outer part of the rod. They are necessary to securely fix it in concrete.
Application of fittings
Almost no modern construction can do without reinforcement. The main purpose of this building material is the reinforcement of concrete structures:
- Foundations and piles.
- Floors.
- Floors.
- Window and door lintels.
- Foundation blocks and more.
To reinforce floors, foundations, piles of other concrete structures that bear significant weight, rods with a diameter of 1.2 to 4 cm are used. In private house construction, a thickness of 1.2-1.4 cm is sufficient for foundation work. For floor reinforcement in In a private house, thinner reinforcement (6-8 mm) is most often used. Now you can move on to calculating how much reinforcement is in meters in a ton.
Weight calculation
So how many meters of reinforcement are in 1 ton? The answer to this question depends, first of all, on the material from which it is made (fiberglass, steel) and the diameter of the product. For calculations, we will take the dimensions most used in private construction.
So, the ratio of the diameter and weight of one linear meter of a steel product:
Diameter, cm | Weight per meter, kg | |
How many meters of fiberglass reinforcement are there in a ton? One of the main advantages of this type of material is its relatively light weight. Another advantage of fiberglass reinforcement is its ease of transportation. It can be transported in a passenger car, as it is lighter and more flexible (it is rolled up into axle boxes in production).
Diameter, cm | Weight per meter, kg | Number of p. meters in 1 ton |
Reinforced concrete today is the most common material used in the construction of multi-story buildings, roads, tunnels, bridges and any other objects. Reinforcement is an important component of such structures - non-reinforced concrete, although it can withstand significant compressive loads, practically does not work in bending and tension, collapsing under relatively small loads. But the use of metal rods - regular or prestressed - eliminates this drawback. Often, builders find themselves in situations where they need to know the weight of reinforcement in order to calculate the required amount of material for construction. A table of reinforcement weights will help them with this. You will find it below in the article, in the reinforcement table, the value of the mass of metal rods of all diameters is presented.
Of course, first of all, the mass of the rod depends on the thickness. The larger the diameter, the greater the weight. Today, in construction, metal rods with a diameter of 6 to 80 millimeters are most often used. The weight of 1 m of reinforcement, the thinnest, weighs only 222 grams, while for the thickest this figure is 39.46 kilograms. As you can see, the difference is huge. Therefore, knowing the weight of the reinforcement will also not be superfluous when calculating the pressure of the structure on the foundation - several unaccounted tons of load can have a detrimental effect on the reliability and durability of any building.
How much does the fittings weigh?
In order to find out the reinforcement weight, the easiest and most convenient way is to use the special table presented below.
Rebar weight table
| Diameter, mm | Weight of 1 meter of reinforcement, kg | Linear meters per ton |
|---|---|---|
| 6 | 0,222 | 4504,5 |
| 8 | 0,395 | 2531,65 |
| 10 | 0,617 | 1620,75 |
| 12 | 0,888 | 1126,13 |
| 14 | 1,21 | 826,45 |
| 16 | 1,58 | 632,91 |
| 18 | 2 | 500 |
| 20 | 2,47 | 404,86 |
| 22 | 2,98 | 335,57 |
| 25 | 3,85 | 259,74 |
| 28 | 4,83 | 207,04 |
| 32 | 6,31 | 158,48 |
| 36 | 7,99 | 125,16 |
| 40 | 9,87 | 101,32 |
| 45 | 12,48 | 80,13 |
| 50 | 15,41 | 64,89 |
| 55 | 18,65 | 53,62 |
| 60 | 22,19 | 45,07 |
| 70 | 30,21 | 33,1 |
| 80 | 39,46 | 25,34 |
All data indicated in this table fully comply with the current GOST. The error can be a maximum of a few percent - such errors will not cause significant trouble and will certainly not cause damage to the structure.
Having a table at hand, you can quickly calculate the weight of reinforcement, for example, with a diameter of 32 mm. Find the corresponding diameter in the first column and immediately find out that its mass is 6.32 kg per 1 m, and a ton includes 158.48 meters.
Why do you need to know the weight?
Professional builders often have a question: what is the weight of a linear meter of reinforcement. Why do they need this? The fact is that when purchasing rods for the construction of large structures, it is not purchased individually, as in individual construction, but in tons. But it’s difficult to calculate how long a certain mass of material will last if you don’t know how much a meter of reinforcement weighs. Knowing the total mass and specific gravity of the reinforcement, 1 meter, you can make simple calculations in a matter of seconds, obtaining the total length of the metal rods. To do this, we take the entire mass of the necessary rods and divide them by the weight of 1 linear meter.
Calculation example
To reinforce the beams, 2.5 tons of 25-diameter rods are required. We take the value of the mass of 1 meter from the table, equal to 3.85 kg. Next, we convert tons to kilograms, multiply by 1000, it will be 2500 kg, and divide by 3.85, we get 649 meters of material. The standard length of a metal rod is 11.7 m, to find out the required number of rods, divide 649 by 11.7, we get 55.5 pieces. In this way, you can count the number of rods with any cross-section. This will help, especially in private construction, to check that the correct amount of material has been delivered to you.
The opposite situation may also occur. The specialist knows how much material he needs, and also knows the optimal diameter. Having found out the theoretical weight of a meter of reinforcement, he just needs to multiply this number by the total length of the required metal rods to determine how much material is needed for construction.
Today we will talk about how much the reinforcement weighs, and the maximum length of a metal rod. Mostly about how many meters are in a ton of reinforcement, but other diameters will also be considered.
Weight of reinforcement, how many meters in 1 ton?
During construction, it is necessary to have an accurate idea of how much weight the entire reinforced structure has as a whole. There are a number of reasons for this:
- This makes it possible to withstand reinforcement technology.
- Guarantees the necessary reliability of the design.
- It is more convenient to calculate the total cost of the structure.
The greatest attention is paid to a rod with a diameter of 12 mm, because this is the minimum diameter value that can be used when creating structures for strip foundations. And of course, we should not forget about the significant factor that during construction, it is very important to know exactly how many meters of reinforcement will be required for one ton of planned products.
How much does the reinforcement weigh and the amount of reinforcement per ton, table:
The weight of a meter of reinforcement is presented in the table of the ratio of diameter and weight of 1 m. Knowing the weight of reinforcing steel according to GOST 5781-82, you can estimate the reinforcement coefficient of the structure (the ratio of the mass of the reinforcement to the volume of concrete) and determine how much material is needed for the foundation (per cube of concrete)
A linear meter of reinforcement is individual reinforcing bars of a smooth and periodic profile 1 meter long, the weight of which depends on the diameter of the reinforcing steel GOST 5781-82 (from a range of diameter sizes of periodic steel - 6, 8.10, 12, 14, 16, 18.20, 22, 25, 28, 32, 36, 40, 45, 50, 55, 60, 70, 80 mm).
| Reinforcement size (nominal bar diameter) | Weight of 1 m of reinforcement, theoretical, kg | Number of meters of reinforcement in 1 ton, m. |
| 4 | 0,099 | 10101,010 |
| 5 | 0,154 | 6493,506 |
| 6 | 0,222 | 4504,504 |
| 8 | 0,395 | 2531,645 |
| 10 | 0,617 | 1620,745 |
| 12 | 0,888 | 1126,126 |
| 14 | 1,210 | 826,446 |
| 16 | 1,580 | 632,911 |
| 18 | 2,000 | 500,000 |
| 20 | 2,470 | 404,858 |
| 22 | 2,980 | 335,570 |
| 25 | 3,850 | 259,740 |
| 28 | 4,830 | 207,037 |
| 32 | 6,310 | 158,478 |
| 36 | 7,990 | 125,156 |
| 40 | 9,870 | 101,317 |
| 45 | 12,480 | 80,128 |
| 50 | 15,410 | 64,892 |
| 55 | 18,650 | 53,619 |
| 60 | 22,190 | 45,065 |
| 70 | 30,210 | 33,101 |
| 80 | 39,460 | 25,342 |
Judging by this table, 1126 meters of reinforcement with a diameter of 12 mm equals one ton of product.
Using this table you can also find out the length of the reinforcement in one kilogram and its weight in one meter of all sizes.
These values will be useful to you when using a metal rod directly if, for example, you need to know what the mass of all the reinforcement used in the construction of a building is. To do this, you just need to add up all the lengths of the reinforcing bars and then multiply the sum by the weight of 1 p/m.
It should be noted that 10 mm reinforcement still exists and is used when pouring foundations. But this occurs only in transverse, that is, in auxiliary reinforcement. In addition to these factors, we should not forget that only those rods that are marked with the symbol “C” are subject to welding.
This whole long process is necessary, since during construction it is necessary to know the length of the reinforcement, and when purchasing it, mass (weight) is important.
Diameters of fittings according to GOST 5781-82
Do not forget that the number of rods per ton can vary, because this directly depends on their length. For example, much fewer rods 10 meters long will be needed than rods with the same diameter but 2 m long.
The number of meters and pieces of reinforcement in 1 ton depends on the diameter of the rod used. It is necessary to know this when purchasing material, so that you can independently check the quantity of goods supplied, as well as calculate the volume of reinforcement for reinforcing monolithic structures.
Footage of reinforcement in ton: calculation example, table
Let's look at an example of how the calculation is made and find out how many meters of reinforcement with a diameter of 12 mm are in 1 ton.
To calculate, we need to know the mass of 1 meter, look, it is equal to 0.888 kg. Now we divide 1000 kg by 0.888 kg, we get 1126.13 m. For convenience, below is a table that immediately indicates the footage of the most popular steel rods in construction.
| Rod diameter, mm. | Number of meters in 1 ton |
| 6 | 4504,5 |
| 8 | 2531,65 |
| 10 | 1620,75 |
| 12 | 1126,13 |
| 14 | 826,45 |
| 16 | 632,91 |
| 18 | 500 |
| 20 | 404,86 |
| 22 | 335,57 |
| 25 | 259,74 |
| 28 | 207,04 |
| 32 | 158,48 |
| 36 | 125,16 |
| 40 | 101,32 |
| 45 | 80,13 |
Knowing how many meters are in 1 ton, you can easily convert the reinforcement from meters to tons. For example: we will convert 8956 m of rods with a diameter of 12 mm into tons. For this, 8956/1126.13=7.953 (t). In this way, any size of whip can be converted by simply dividing the total length by the length of 1000 kg.
Number of reinforcement pieces per ton: calculation example, table
Knowing the footage of the rods in 1000 kg, you can make calculations by the piece. Let’s also look at how to do this using an example, let’s calculate how many pieces of 12 mm reinforcement are in 1 ton, 12 m long and 11.7 m long (the most common lengths produced by factories).
To calculate the number of pieces, we take the total footage in one ton, for rods 12 mm long, it is equal to 1126.13 m, and divide by the length of the rod 12 m, we get 93.84 pieces, for a rod 11.7 m long, the result is 96.25 pieces . The table below shows the number of whips of the most common sizes (calculated values are rounded to the nearest tenth).
| Diameter of fittings, mm. | Number of pieces per ton of rods 11.7 m long. | Quantity for rod length 12 m. |
| 6 | 385 | 375,4 |
| 8 | 216,4 | 211 |
| 10 | 138,5 | 135 |
| 12 | 96,2 | 93,8 |
| 14 | 70,6 | 68,9 |
| 16 | 54,1 | 52,7 |
| 18 | 42,7 | 41,7 |
| 20 | 34,6 | 33,7 |
| 22 | 28,7 | 28 |
| 25 | 22,2 | 21,6 |
| 28 | 17,7 | 17,2 |
| 32 | 13,5 | 13,2 |
| 36 | 10,7 | 10,4 |
| 40 | 8,6 | 8,4 |
| 45 | 6,8 | 6,7 |
An example of calculation using a table: let’s say for an armored belt you need 600 kg of 10 mm reinforcement. In order to make it convenient to transport, 12 meter rods were cut into 6 m lengths. To find out their number, take the table value of 135 (pieces per ton) and multiply by 0.6, equal to 81 pieces. Since they were divided in half, we multiply 81 by 2, we get 162 rods of 6 meters each.
Do not forget that when cutting reinforcement into short rods, its consumption for reinforcing the structure increases, since more overlaps will have to be made. It is worth taking this into account when calculating and purchasing materials for construction.
According to these tables, you can calculate the required tonnage of rods for a monolithic belt and other reinforcing structures, based on the footage of the building. And also, you can calculate for yourself whether the material was brought to you correctly by recalculating its quantity.